Refer to figure.
A helicopter Pilot extracts from the Aircraft Flight Manual that the maximum crosswind component is 17 kt during approach/landing. If the wind is 270/20kt, how many degrees to the left or right relative to the wind direction may the approach/landing direction be without exceeding the crosswind limit?
Refer to figure.
The figure helps to determine the Head/Tailwind and Crosswind Components.
For this question determine the Maximum Angle Between Wind Direction and Approach/Landing Direction with the following manner:
- Enter the graph from the horizontal axis with Maximum Crosswind Component 17 kt and draw a vertical line.
- Follow the arc of 20 kt as indicated until crossing the vertical line.
- The intersection lies on the radius 58º, which is the Maximum Angle Between the Wind Direction and the Approach/Landing Direction.
That means that, the helicopter may has its approach/landing direction left or right relative to the wind direction not more than 58º to stay within the crosswind limit of 17 kt, i.e the helicopter's approach/landing direction should be between 270º - 58º = 212º and 270º + 58º = 328º.
NOTES:
This graph is not in CAP 758, but actually in CAP 698 for fixed-wing performance and according to feedback it has appeared in exam questions.
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This question has appeared on the real examination, you can find the related countries below.
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Austro Control5
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Switzerland2
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Bulgaria1
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Czech Republic1
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Germany1