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Given:

Distance from departure to destination: 2200 NM
True track: 150°
W/V: 330/50
TAS: 460 kt

What is the distance and time of the PET from the departure point?

  • A
    Distance: 980 NM Time: 144 min
  • B
    Distance: 1120 NM Time: 179 min
  • C
    Distance: 980 NM Time: 115 min
  • D
    Distance: 1100 NM Time: 179 min

Refer to figure.
Solving from Heading (HDG) & Ground Speed (GS), knowing WV, TAS and required track.

1. Set wind direction to 330º under the "TRUE HEADING" index at the top.
2. Set the center point on the True Airspeed (TAS) of 460 kt.
3. Mark the wind velocity 50 kt down from the centre point.
4. Initially, set the True Track under the "TRUE HEADING" index.

  • GS home: 330º
5. The groundspeed for this track is approximately 410 kt.
  • GS out: 150º

5. The groundspeed for this track is approximately 510 kt.

We can now apply the formulas:
Distance to PET = (GS home x Distance) / (GS out + GS home)
Distance to PET = (410 x 2200) / (510 + 410)
Distance to PET = 980 NM

Time to PET = Distance to PET / GS out
Time to PET = 980 NM / 510 kt = 1 h 55 min = approx. 115 min

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