An aircraft should take-off with (into) the wind. When taking off with a headwind it slows down the plane in its acceleration respect to the ground, but increases the flow of air over the wings, allowing to take off in a shorter distance and climbing in a greater angle in order to clear any obstacle.
Therefore, to solve this exercise we have to choose the option where headwind component is the greatest and the crosswind component is the smallest:
-
Crosswind speed = wind speed x sin ( α )
-
Headwind speed (or tailwind) = wind speed x cos ( α )
Wind direction 040º, wind speed 20 kt:
-
RWY 06: crosswind = 7 kt; headwind = 19 kt
RWY 06 take-off direction is 060º, with wind coming from 040º: greatest headwind with the least crosswind component. -
RWY 08: crosswind = 13kt; headwind = 15 kt
-
RWY 09: crosswind = 15 kt; headwind = 13 kt
-
RWY 12: crosswind = 20 kt; headwind = 4 kt
Your Notes (not visible to others)
This question has appeared on the real examination, you can find the related countries below.