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An aircraft is planning to take-off from RWY35 (347°M). Determine the average crosswind component for the take-off, given:

Variation: 5ºW
ATIS wind: 050º/20G30

  • A
    15 kt
  • B
    18 kt
  • C
    21 kt
  • D
    27 kt
  • ATIS and tower: reported winds are referenced to magnetic north.
  • The question refers to the average wind (not the maximum wind component): 20 kt

The crosswind component is equal to the speed (V) of the wind multiplied by the sine of the angular difference (XWC = V × Sin θ)

Wind direction: 050ºM
Runway Direction: 347ºM
Angular difference = 063º
  • XWC = 20 kt x sin 63º
    XWC = 17.8 kt (approx. 18 kt)

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