The total mass of a helicopter is 9 000 kg and the Centre of Gravity position is at 2.0 m from the datum line. The aft limit of CG is at 2.1 m from the datum line. What mass of cargo must be shifted from the front cargo hold (at 0.8 m from the datum) to the aft cargo hold (at 3.8 m), in order to move the CG to the aft limit?
The Centre of Gravity must be displaced to the aft CG limit by: 2.1 m - 2.0 m = 0.1 m (Change of CG)
The distance between the front and rear cargo hold is: 3.8 m - 0.8 m = 3 m (Distance moved).
For this question the following "Shifting Load" formula helps to find out the mass of cargo that needs to be moved from the front cargo hold to the rear cargo hold, in order to move the CG to the aft limit:
- Mass change / Total mass = Change of CG / Distance moved.
Solving for Mass change, we get the mass that must be shifted:
- Mass change = (Total mass x Change of CG) / Distance moved = (9 000 kg x 0.1 m) / 3 m = 300 kg.
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