Given the following information, calculate the remaining fuel amount that should be left within the helicopter's tanks, with 1 hour and 45 minutes remaining flight time until the destination:
Total Trip time: 04:15
Reserve fuel: 30% of Trip fuel
Start-up/Taxi fuel: 15 kg
Block fuel: 1 050 kg
For this category of questions, proceed with the following manner:
1. Take-off fuel = Trip fuel + 30% Trip fuel = 130% Trip fuel or Take-off fuel = 1.3 x Trip fuel.
2. Also, Take-off fuel = Block fuel - Start-up & Taxi fuel = 1 050 kg - 15 kg = 1 035 kg.
3. Thus, we get the following equation: 1.3 x Trip fuel = 1 035 kg.
4. Solving for Trip fuel, we get: Trip fuel = 1 035 kg / 1.3 = 796.1 kg.
5. So, the Trip fuel flow is: Trip fuel / Trip time = 796.1 kg / 4.25 hr = 187.3 kg/hr.
6. The Trip time from take-off to the current position is: 4.25 hr - 1.75 hr (or 04:15 - 01:45) = 2.5 hr (or 02:30).
7. After 2.5 hr, the Trip fuel used will be: 187.3 kg/hr x 2.5 hr = 468.25 kg.
8. Therefore, the fuel remaining after 2.5 hr will be: Take-off fuel - Trip fuel used = 1 035 kg - 468.25 kg = 566.75 kg, closest answer 568 kg.
NOTE:
The question asks for the remaining fuel amount after a flight of: 04:15 - 01:45 = 02:30.
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