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How much is the clearance passing the highest obstacle in the following scenario? An aircraft is flying at FL170 in mountainous terrain on the northern side of the alps and the charted minimum grid-area altitude is 16 200 feet.

The outside air temperature at FL170 is -29°C 
The QNH is 1000.25 hPa given by a meteorological station with elevation 13 500 feet. 
Assume 1hPa = 30 feet

  • A
    2120 ft
  • B
    286 ft
  • C
    2286 ft
  • D
    2676 ft

Refer to figure.
In this question, we are given a pressure altitude (in the form of a flight level) and are asked for the terrain clearance, therefore we need to determine the corresponding true altitude.

The first step is to compute the pressure correction by considering the deviation from the standard mean sea level pressure of 1013 hPa: 1013 hPa - 1000 hPa = 13 hPa. Since the barometric lapse rate near the surface is 30 ft/hPa, the pressure correction can be calculated as follows: Pressure correction = 13 hPa x 30 ft/hPa = ­­­390 ft. This value needs to be subtracted from the pressure altitude as per the rules below:

Indicated altitude = 17 000 ft - 390 ft = 16 610 ft.

To determine the temperature correction, it is necessary to have knowledge of the ISA air temperature for the given flight level/altitude (FL170). In the International Standard Atmosphere (ISA), the air temperature at sea level is 15°C, and the temperature lapse rate is -2°C/1000 ft. The formula to calculate the ISA temperature is therefore: ISA temperature = 15°C - (17 000/1 000) x 2, giving an ISA temperature of ­­­-19°C. The actual outside air temperature is ­­­-29°C, which means we have an ISA deviation of ISA -10°C.

Next, we need to determine the temperature correction. The ISA deviation is ISA -10°C. The elevation of the aerodrome has to be taken into account: 16 610 ft - 13 500 ft = 3110 ft. Based on the 4% rule and its calculation mentioned in the rules below, the height correction for the temperature can be calculated as follows: Height correction for temperature = 4 × (-10) × (3110/1000) = 124 ft.

The temperature correction is subtracted from the indicated altitude as per the rules below, to give a true altitude of 16 610 ft - 124 ft = ­­­­­16 486 ft.

The charted minimum grid altitude 16 200 ft in a mountainous terrain means that, an aircraft flying within this grid clears the highest obstacle by 2000 ft. Thus, the highest obstacle is at: 16 200 ft - 2000 ft = 14 200 ft.

Therefore, the aircraft clears the obstacle by: 16 486 ft - 14 200 ft = 2286 ft.


RULES. The following rules should be considered for altimetry calculations:

  • All calculations are based on rounded pressure values to the nearest lower hPa.
  • The value for the barometric lapse rate between MSL and 500 hPa to be used is 30 ft/hPa as an acceptable approximation of the barometric lapse rate.
  • To determine the true altitude/height, the following rule of thumb, called the ‘4 %-rule’, shall be used: the altitude/height changes by 4% for each 10°C temperature deviation from ISA.
    For simplification: Height correction for the temp = 4 × (ISA DEV) × Indicated alt/1000 = ___ ft
  • If no further information is given, the deviation of the outside-air temperature from ISA is considered to be the same throughout the whole layer.
  • The elevation of the aerodrome has to be taken into account. The temperature correction has to be considered for the layer between the station (usually an aerodrome) and the position of the aircraft.

IF

THEN

Higher pressure
 

Indicated Altitude > Pressure Altitude

Lower pressure
 

Indicated Altitude < Pressure Altitude

Warmer than ISA
 

True Altitude > Indicated Altitude

Colder than ISA
 

True Altitude < Indicated Altitude

Definitions
Pressure Altitude: The altimeter indication with standard pressure (1013.2 hPa) set.
Indicated Altitude: The altimeter indication with local QNH set.
True altitude: The actual altitude of the aircraft above mean sea level.

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