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After flying for 16 min at 100 kt TAS with a 20 kt tail wind component, you have to return to the airfield of departure. Assuming a turn rate of 3°/s, you will arrive overhead the airfield after…

  • A
    21 min.
  • B
    11 min 40 sec.
  • C
    16 min.
  • D
    25 min.

1) Calculate the Ground Speed:
TAS: 100 kt
During the outbound leg we will experience a 20 kt tailwind:

  • Ground Speed Out = TAS + Tailwind = 100 kt + 20 kt = 120 kt

During the return leg we will experience a 20 kt headwind:

  • Ground Speed Return = TAS - headwind = 100 kt - 20 kt = 80 kt

2) Calculate Distance flown after 16 min:
120 kt x 16 min = 32 NM 

3) Calculate Return leg Flight time:
32 NM / 80 kt = 24 min 

4) Calculate time taken to fly a 180° turn:
180° : 3°/sec = 60 sec = 1 min  

=> You will arrive overhead the airfield after: 24 min + 1 min = 25 min 

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