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Given:

Distance from departure to destination: 1950 NM
GS Out: 400 kt
GS Home: 300 kt

What is the time of the PET from the departure point?

  • A
    167 min
  • B
    125 min
  • C
    29 min
  • D
    223 min

Note: Since the terms PET and PSR are not present in EASA Air Ops, these questions are less likely to appear in the exam.

Distance to PET = Distance x GS Home / (GS out + GS Home)

Time to PET = Distance to PET / GS Out

1950 NM x 300 kts / (400 kts + 300 kts) = 836 NM

836 NM / 400 kts = 2.09 hrs / 125 mins

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This question has appeared on the real examination, you can find the related countries below.

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