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In a steady and unaccelerated helicopter flight, with the main rotor lift vector acting slightly in front of the Centre of Gravity, which combination of the following statements is correct?

1. Lift equals weight
2. Lift equals drag
3. Thrust equals weight
4. Thrust equals drag

  • A

    1 and 2

  • B

    2 and 3

  • C

    2 and 4

  • D

    1 and 4

Refer to figure.
Note: This question appeared in EASA ATPL(H) Exams differentiating what we already know regarding the forces acting on a helicopter in a straight and level accelerated flight (Horizontal component of TRT opposes Drag; Vertical component of TRT opposes Weight). In other words, it assumes as Thrust the Horizontal component of TRT and as Lift the Vertical component of TRT. This questions matches more with ATPL(A) exams question, where the basic fources are:

  • Thrust generated by the engines opposes Drag.
  • Lift acting through the wings' Centre of Pressure opposes Weight.

Also, we are not sure for the exact wording. Thus, further feedback would be appreciated.

The basic forces acting on an aircraft in a straight and level accelerated flight are:

  • Thrust (Horizontal component of TRT) opposing Drag.
  • Lift (Vertical component of TRT) opposing Weight.

Where:

  • Thrust allows the aircraft to move horizontally.
  • Lift maintains the aircraft airborne.
  • Weight is the gravitional force acting through the Centre of Gravity.
  • Drag resists the aircraft's movement through the air.

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This question has appeared on the real examination, you can find the related countries below.

  • Greece
    1
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