15 / 20
The still air distance in the climb is 189 Nautical Air Miles (NAM) and time 30 minutes. What ground distance would be covered in a 30 kt head wind?
  • A
    203 NM
  • B
    174 NM
  • C
    188 NM
  • D
    193 NM

The aircraft covers an air distance of 189 NAM in 30 min, so its True airspeed is: TAS = NAM / Time = 189 NM / 0.5 hr = 378 kt.

Also, experiencing a headwind of 30 kt during climb, its Groundspeed is: GS = TAS - Headwind component = 378 kt - 30 kt = 348 kt.

Thus, the ground distance covered during climb will be: NGM = GS x Time = 348 kt x 0.5 hr = 174 NM.

Your Notes (not visible to others)



This question has appeared on the real examination, you can find the related countries below.