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From a latitude of 10ºN, an aircraft flies south at a groundspeed of 444 km/h for 3 hours to position B. What will be its latitude at B?
  • A
    02°S
  • B
    0°N/S
  • C
    12°S
  • D
    02°N

Degrees of latitude are always 60 nautical miles apart (1º of latitude equals 60 NM).

  • Distance covered in 3 hours at 444 km/h:
    3 h x 444 km/h = 1332 km

  • Now, we must convert km into NM:
    1 NM = 1.852 km
    Therefore, 1332 km equals 719 NM (1 332 km / 1.852)

LATITUDE CHANGE:

1º of latitude = 60 NM
719 NM = 11º59' (Approx. 12º)

=> Flying 12º South from 10ºN, the aircraft will end up at 2ºS.

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