For the swept wing aircraft, it is more convenient, for aerodynamic purposes, to relate the CG position to the Mean Aerodynamic Chord (MAC) of a wing. In this case the CG is expressed as a percentage of its position along the MAC (%MAC) from the leading edge (LEMAC).

For this question:

• 30% MAC means that the CG is 30% along the MAC length (4.60 m), which corresponds to: 4.60 m x 0.3 = 1.38 m aft from the LEMAC. So, its initial CG position is: 14 m + 1.38 m = 15.38 m aft from the reference datum.
• 33% MAC means that the CG is 33% along the MAC length (4.60 m), which corresponds to: 4.60 m x 0.33 = 1.518 m aft from the LEMAC. So, its CG re-position will be: 14 m + 1.518 m = 15.518 m aft from the reference datum.

So, the CG change is: 15.518 m - 15.38 m = 0.138 m, which means that after the new cargo load distribution, the CG moves more aft, because portion of the front cargo is transferred to the rear cargo compartment.

The amount of mass which is transferred to the rear cargo compartment can be found applying the "Shifting Load" formula: Mass Change / Total Mass = Change of CG / Distance Moved.
Solving for Mass Change, we get: Mass Change = Change of CG x Total Mass / Distance Moved = 0.138 m x 200 000 kg / (25 m -15 m) = 2 760 kg.

Therefore, the new distribution load will be:

• Front Cargo: 6 500 kg - 2 760 kg = 3 740 kg.
• Rear Cargo: 4 000 kg + 2 760 kg = 6 760 kg.