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Refer to figure.
What are the take-off speeds for a balanced field take-off from an airport at 1200 ft of elevation, runway 25 with 1% downwhill slope. The current weather conditions are: 07005kts 9999 BKN020 20/15 Q1003. The expected take-off mass of the aircraft is 320 tonnes.

  • A
    140/154/169
  • B
    136/150/169
  • C
    136/154/169
  • D
    138/152/169

Refer to figure.
(1) Calculate the Pressure Altitude of the airfield:

The airfield elevation is 1200 ft, however the local QNH equals 1003 hPa.
1013 – 1003 = 10
10 x 30 (ft/hPa) = 300ft.
The pressure altitude of the airfield is 1200 ft + 300 ft = 1500 ft

(2) Enter the upper right graph at a temperature of +20°C – which is the temperature indicated in the METAR – and stop at PA of 1500 ft => the graph shows band B (it's actually right on the border).

(3) Using the main table, look for the mass of 320 000 kg and intersect with band “B”. The corresponding basic V1/VR/V2 are:

140/154/169.

(4) Using the upper left corner table, find the correction that must be made for runway slope and wind – which is only applied to V1.

  1. Question text indicates that there is a 1% downslope and a 5 kt tailwind (250° – 70° = 180°). Thus, we have to apply a correction for this as indicated:
  2. – 2kts for downslope and –2 kts for TW.

=> V1 = 140 – 4 = 136, VR = 154 and V2 = 169.

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