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Given:

Distance from departure to destination: 2450 NM
Safe Endurance: 7.5 h
TAS: 410 kt
Ground Speed Out: 360 kt
Ground Speed Home: 460 kt

What is the time of the PSR from the departure point?

  • A
    252 min
  • B
    111 min
  • C
    198 min
  • D
    156 min

Note: Since the terms PET and PSR are not present in EASA Air Ops, these questions are less likely to appear in the exam.

Distance to Point of Safe Return = Endurance x GS OUT x GS home / (GS out + GS home)

Time from point of departure to PSR = Distance to PSR / GS out

7.5 hrs x 360 kts x 460 kts / (360 kts + 460 kts) = 1515 NM

1515 NM / 360 kts = 4.2 Hrs = 252 min

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This question has appeared on the real examination, you can find the related countries below.

  • Pakistan
    3
  • Greece
    1
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