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Refer to figures.
Given:

Mass at brake release: 190 000 kg 
Selected cruise speed: 0.82 Mach 
Flight leg distance: 1500 NM 
Cruise level: optimum 
Air conditioning: standard 
Anti-icing: OFF 
Temperature: ISA 
CG: 37% Assuming zero wind

The planned flight time from take-off to landing needed to complete this flight will be…

  • A
    203 minutes
  • B
    209 minutes
  • C
    198 minutes
  • D
    192 minutes

Refer to figures.
1. Enter the table on the first column and find the value "190" (which corresponds to 190 000 kg) and intersect with "0" (0 hundreds of kg) - read the corresponding value: 6417 NAM and 819 min.

2. From the above distance, deduct the air distance of 1500 NM we must cover = 6417 NM - 1500 NM = 4917 NM.

4. On the table, find the timing corresponding to 4917 NM.

  • There is no distance corresponding to 4917 NM - However, we can use the timings for 4916 NM which is close enough => 627 min.

5. Find the time necessary to fly 1500 NM.

  • It will be the difference between 819 min and 627 min = 192 min

6. Apply the "Climb Correction"

  • For "Optimum FL" and 0.82 M => a correction of 6 min must be added.

192 min + 6 min = 198 min

7. Apply the "Descent Correction"

  • 0.82 M and from optimum FL => we must apply a correction of 11 min

198 min + 11 min = 209 min

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