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Given:

Distance from departure to destination: 950 NM
GS Out: 275 kt
GS Home: 225 kt

What is the time of the PET from the departure point?

  • A
    93 min
  • B
    39 min
  • C
    139 min
  • D
    114 min

Note: As per the latest EASA syllabus, no questions address this learning objective. However, they are still part of the UK CAA syllabus, as also confirmed by recent feedback.

Distance to PET = Distance x GS Home / (GS out + GS Home)

Time to PET = Distance to PET / GS Out

950 NM x 225 kts / (275 kts + 225 kts) = 428 NM

428 NM / 275 kts = 1.55 Hrs / 93 min

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This question has appeared on the real examination, you can find the related countries below.

  • Pakistan
    3
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