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An aircraft is climbing from 3000 ft to 8000 ft on a 3° path at an average GS of 210 kt. The altitude of 8000 ft will be reached in (1) _____ and the ground distance covered will be (2) _____.

  • A

    (1) 4 minutes and 46 seconds; (2) 16.7 NM

  • B

    (1) 5 minutes and 14 seconds; (2) 18.3 NM

  • C

    (1) 12 minutes and 42 seconds; (2) 44.5 NM

  • D

    (1) 7 minutes and 56 seconds; (2) 27.8 NM

1. For a climb with 3◦ path the rate of climb can be found by the formula:

Rate of Climb (fpm) = 5 x Ground Speed (knots) = 5 x 210 = 1050 fpm

2. The time to climb from 3000 ft to 8000 ft is:

Time to climb (min) = Height difference (ft) / ROC (fpm) = (8000 ft - 3000 ft) / 1050 fpm = 4.76 min or 4 min and 46 sec.

3. The Ground distance covered during the climb is:

Ground distance (NM) = GS (knots) x Time (hours) = 210 kt x 4.76/60 hr = 16.7 NM.

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