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Given:

Distance from departure to destination: 2500 NM
GS Out: 540 kt
GS Home: 470 kt

What is the time of the PET from the departure point?

  • A
    129 min
  • B
    171 min
  • C
    28 min
  • D
    149 min
To solve this exercises, use the following formulas:
Distance to PET = (GS home x Distance) / (GS out + GS home)
  • Distance to PET = (470 x 2 500) / (540 + 470)
  • Distance to PET = 1163 NM
Time to PET = Distance to PET / GS out
Time to PET = 1 163 / 540 = 2.15 h = approx. 129 min

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