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When reviewing the wind charts in the briefing room, you notice that the average wind in cruise will be 25 kt headwind.Given following data, what will be the flight time to destination?

Time to top of climb : 30 min
Cruise leg: 740 NM
FL380
TAS: 460 kt
ISA -10°C
Time to from top of descent to landing : 22 minutes

  • A
    2 h 34 mins
  • B
    1 h 36 mins
  • C
    1 h 42 mins
  • D
    2 h 28 mins

Cruise GS = 460-25 = 435.

Distance 740/GS 435 = 1 hr 42 minutes = 102 minutes.

So 30 (Time to climb)+ 102 (Cruise)+ 22( Time to descent) = 154 minutes = 2 hr 34 mins.

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