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(For this question use annex 033-036 and 033-038 rev. 05.11.2004).
Assuming the following data below, what is the time needed to carry out such a flight?

Ground distance to be covered: 2000 NM
Cruise flight level: FL330
Cruising speed: Mach 0.82 (true airspeed: 470 kt)
Head wind component: 30 kt
Planned destination landing mass: 160 000 kg
Temperature: ISA
CG: 37%
Total anti-ice: ON
Pack flow: HI

  • A
    4 hours 43 minutes
  • B
    5 hours 02 minutes
  • C
    4 hours 26 minutes
  • D
    4 hours 10 minutes

Refer to figure.

1. Convert 2000 NGM to NAM, in order to enter the table.
Use the formula: NAM = NM x TAS / GS = 2000 x 470 / 440 = 2136 NAM

2. On the first column, under "AIR DIST." look for 2136 NAM.
There is no distance of 2136 NAM on the table. Therefore, we have to interpolate between 2100 NAM and 2200 NAM.
Intersect 2100 NAM and 2200 NAM with FL330:

  • For 2100 NAM = 4.39 (4 h 39 min)
  • For 2200 NAM = 4.51 (4 h 51 min)
After interpolation, find a timing of 4 h 43 min (4.43) for 2136 NAM.

Note: On the table, time is given as H.MIN.

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