6 / 20
Refer to figure.
Calculate the fuel required to an alternate located 80 NM away at an approximate landing weight of 50000 kg and a headwind of 20 knots.
  • A
    780 kg
  • B
    744 kg
  • C
    900 kg
  • D
    822 kg

Refer to figure.

According to the first table "Ground to Air Miles Conversion" for a 20 kt headwind:

  • If the ground distance = 50 NM, the air distance = 55 NM;
  • If the ground distance = 100 NM, the air distance = 108 NM.
To find the air distance corresponding to 80 NM ground distance we must interpolate:
  • From the ground distance of 50 NM to 100 NM, the air distance increases by 53 NM (108 - 55);
  • Therefore, when the ground distance increases by 30 NM (50 NM to 80 NM), the air distance will increase by:

    NAM = (30 x 53) / 50 NM = 32 NM

An Ground Distance of 80 NM corresponds to an Air Distance of: 55 NM + 32 NM = 87 NM
According to the second table "Trip Fuel and Time Required":
  • If the air distance = 50 NM and landing weight = 50 000 kg => fuel required equals 600 kg;
  • If the air distance = 100 NM, and landing weight = 50 000 kg => fuel required equals 900 kg;
To find the fuel required corresponding to 87 NM air distance we must interpolate:
  • From the air distance of 50 NM to 100 NM, the fuel required increases by 300 kg;
  • Therefore, when the air distance increases by 37 NM (50 NM to 87 NM), the fuel required will increase by:

    Fuel required = (300 x 37) / 50 = 222 kg
The Fuel required to the alternate (air distance of 87 NM) equals = 600 kg + 222 kg = 822 kg

Your Notes (not visible to others)



This question has appeared on the real examination, you can find the related countries below.

  • United Kingdom
    23
  • Austro Control
    19
  • Portugal
    10
  • Greece
    7
  • Spain
    6
  • Germany
    3
  • Hungary
    3
  • Romania
    3
  • Ireland
    2
  • Malta
    2
  • Norway
    2
  • Poland
    2
  • Czech Republic
    1
  • Denmark
    1
  • Italy
    1
  • Lithuania
    1
  • Netherlands
    1
  • Slovenia
    1
  • Sweden
    1