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The elevation of the departure airport is 2500 ft. An aircraft has to climb to FL105 with a rate of climb of 750 ft/min. The QNH is 995 hPa. Determine the climb time.

  • A
    12 min.
  • B
    11 min.
  • C
    9 min.
  • D
    10 min.

Cruise altitude = 10500 - ((1013- 995) x 30) = 9960 feet

Climb time = (9960 - 2500) / 750 = 9.94 minutes

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