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An aircraft departs point A (26°06'N,004°11'E) and flies directly south for 500 NM to point B. From point B, the aircraft flies directly east for 500 NM to point C. The coordinates of point C are…
  • A
    17°42'N, 012°31'E.
  • B
    17°30'N, 012°31'E.
  • C
    17°46'N, 012°56'E.
  • D
    17°45'N, 008°20'E.

The aircraft initially flies south, so it flies along the meridian 004°11'E. Along a meridian "1 minute of latitude equals to 1 NM". Thus, a distance of 500 NM along a meridian corresponds to 500' change of latitude or 8° 20'.

Therefore, as it flies south on the northern hemisphere, its latitude will decrease, provided that it does not cross the Equator. Its new latitude at B point, after 500 NM south off A point, will be: 

  • 26°06'N - 8° 20' = 17°46'N.

After B point, the aircraft continues eastwards (i.e. along the same parallel of latitude) for 500 NM along the 17°46'N parallel of latitude. The distance along a parallel of latitude is called "Departure" and is given by the formula: 

  • Departure(NM) = Change of Longitude(min) x cos Lat.

Solving for Change of Longitude we get: 

  • Change of Longitude(min) = Departure(NM) / cos Lat = 500 NM / cos 17°46' = 525 or 8° 45'.

Therefore, its new longitude, after 500 NM east off B point, will be: 

  • 004°11' + 8° 45' = 012°56' E.

Finally, C position's coordinates will be: 17°46'N 012°56' E.

 

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