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Refer to figure.
The Basic Empty Mass and longitudinal CG position of the aircraft are 6 000 kg and 4.70 m. The mass of the pilot is 90 kg, the mass of the co-pilot is 100 kg, the mass of the flight engineer is 80 kg. The longitudinal CG position at Dry Operating Mass is:

  • A
    4.594 m
  • B
    5.012 m
  • C
    4.796 m
  • D
    4.610 m

Refer to figure.
Dry Operating Mass (DOM) is the basic empty mass (BEM) and the variable load (VL).

The Variable Load consists of the crew, their baggage and any removable equipment that is required for the flight (catering, service equipment, food, beverages etc.).

The Moment is the turning force created by the mass acting over a distance or lever arm and is calculated by multiplying the arm by the mass: Moment = Mass x Arm.

For this question, the DOM is: DOM = BEM + VL = 6 000 kg + 90 kg + 100 kg + 80 kg = 6 270 kg.

Generally, the CG position can be found by adding all the moments and then dividing the total moment by the total mass. The total mass for this question is the DOM.

Thus, the longitudinal CG position at Dry Operating Mass is: CG DOM = DOM Moment / DOM = 28 803 kg.m / 6 270 kg = 4.594 m.

ITEM MASS ARM MOMENT
BEM 6 000 kg 4.70 m 28 200 kg.m
PILOT 90 kg 184 kg.m
CO-PILOT 100 kg 204 kg.m
FE 80 kg 215 kg.m
DOM 6 270 kg 28 803 kg.m

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