An aeroplane with one nose landing gear and two main landing gears is weighed on jacks. Based on the following readouts, what is the aircraft BEM and CG position?
Nose jack positioned at 161 inches aft of datum reading: 6848 kg
Each main wheel jack positioned at 757 inches aft of datum reading: 11 873 kg
The nose gear wheel load is 6848 kg.
The main gear wheels load is 2 x 11 873 kg = 23 746 kg (two wheels with a single wheel load of 11 873 kg).
Total mass of aircraft = BEM = 6848 kg + 23 746 kg = 30 594 kg
Moment is the turning force created by the mass acting over a distance or arm and is calculated by multiplying the arm by the mass or weight:
- Moment = Arm x Mass or Weight.
Moments aft of the datum are by convention positive and moments forward of the datum are negative.
The Centre of Gravity (CG) can be found by adding all the moments and then dividing the total moment by the total mass or weight:
- CG =Total Moment / Total Weight.
CG = Total Moment / Total Weight = [(23 746 kg x 757 in) + (6848 kg x 161 in)] / 30 594 kg = 19 078 250 kg in / 30 594 kg = 623.6 in aft of datum.
Your Notes (not visible to others)
This question has appeared on the real examination, you can find the related countries below.
-
Spain17
-
United Kingdom7
-
France5
-
Czech Republic4
-
Austro Control3
-
Pakistan3
-
Romania3
-
Bulgaria2
-
Italy2
-
Poland2
-
Iceland1
-
Ireland1
-
Luxembourg1
-
Malta1
-
Slovakia1
-
Sweden1
-
Switzerland1
-
Thailand1
Use Keyboard Shortcuts
