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Given:

True course from A to B: 250°
Ground distance: 210 NM
TAS: 130 kt
Headwind component: 15 kt
Estimated time of departure (ETD): 0915 UTC

The estimated time of arrival (ETA) is...

  • A

    1115 UTC.

  • B

    1105 UTC.

  • C

    1005 UTC.

  • D

    1052 UTC.

To calculate times in navigation, the Groundspeed (GS) is required, which is equal to:

  • GS = TAS + Tailwind component, or
  • GS = TAS - Headwind component

For this question, GS = TAS - Headwind component = 130 kt - 15 kt = 115 kt.

The ground distance covered is 210 NM. Thus, the flight time required is: Ground Distance / GS = 210 NM / 115 kt = 1.82 hr or 01:50 approximately.

Thus, the Estimated Time of Arrival (ETA) is: ETD + Flight time = 09:15 UTC + 01:50 = 11:05 UTC.


NOTE:

To convert the time from HH:MM to a decimal form, proceed as:

  • 1.82 hr = 01 hour and 0.82x60 min = 01 hour and 49.2 min.

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