10 / 20

An aircraft is flying with a true airspeed (TAS) of 180 kt and a headwind component of 25 kt for 2 hours and 25 minutes. The distance flown equals...

  • A

    693 NM.

  • B

    435 NM.

  • C

    375 NM.

  • D

    202 NM.

To calculate times in navigation, the Groundspeed (GS) is required, which is equal to:

  • GS = TAS + Tailwind component, or
  • GS = TAS - Headwind component

For this question, GS = TAS - Headwind component = 180 kt - 25 kt = 155 kt.

The required flight time is given by the formula:

  • Distance = Groundspeed x Flight time

So, for with a Groundspeed of 155 kt for 2 hours and 25 minutes (or 2.42 hr), the distance flown is:

  • Distance = 155 kt x 2.42 hr = 375 kt.

Your Notes (not visible to others)



This question has appeared on the real examination, you can find the related countries below.

  • Austro Control
    1
Keyboard Shortcut Use Keyboard Shortcuts