An aeroplane has a heading of 090°. The distance which has to be flown is 90 NM. After 45 NM the aeroplane is 4.5 NM north of the planned flight path. What is the corrected heading to reach the arrival aerodrome directly?
Refer to figure.
Using your Flight/Nav computer, the corrections that must be made to the heading are:
- Degrees to parallel: Align distance off, 4.5 NM (45) outer scale, with distance travelled, 45 NM inner scale. Above the black arrow (60), read the degrees to parallel: 6° (60) on the outer scale.
- Degrees to intercept position B: Align distance off, 4.5 NM (45) outer scale, with distance to go, 45 NM inner scale. Above the black arrow (60), read the degrees to intercept: 6° (60) on outer scale.
Thus, the total heading correction to proceed directly to position B is: 6° + 6° = 12°. And since the deviation is to the north (left), the heading correction must be to the south (right).
An alternative way to calculate the course change to reach B directly based on the 1:60 rule, which states that: "For each degree of track error you will be one NM off-track having travelled 60 NM along track" is:
- Degrees to parallel = (Distance off track x 60) / Miles travelled = (4.5 NM x 60) / 45 NM = 6°.
- Degrees to intercept = (Distance off track x 60) / Miles to go = (4.5 NM x 60) / (90 NM - 45 NM) = 6°.
Thus, the total heading correction to proceed directly to position B is: 6° + 6° = 12°. And since the deviation is to the north (left), the heading correction must be to the south (right).
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