Given a pressure altitude of 3700 ft and a QNH of 1024 hPa, what is the actual airfield elevation above mean sea level?
This question reverses the standard pressure altitude conversion. Given pressure altitude and QNH, we have to find the elevation.
Elevation = Pressure altitude + (QNH - 1013) x 30 ft
QNH = 1024 hPa. Deviation from standard = 1024 - 1013 = +11 hPa.
If QNH is HIGHER than 1013, the actual pressure is greater than standard for that elevation, meaning the elevation is HIGHER than the pressure altitude.
Correction = 11 x 30 = 330 ft added to pressure altitude.
Elevation = 3700 + 330 = 4030 ft
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