Refer to figure.
Note: This question is similar to 902064.

From the coordinates, the aircraft is traveling in a south-easterly direction. However, since both latitude and longitude are changing, we must calculate the distance of both components.

1. LATITUDE CALCULATION
Step 1: Calculate the change in latitude (ch.lat)

• For same hemispheres, subtract the smaller latitude from the larger one.
• For different hemispheres, add the two latitudes.

Since both positions lie in the Southern Hemisphere, we will subtract the latitudes. Therefore,

• Change in latitude = S29°58' - S26°42'
• Change in latitude = 3°16'S*

* We are travelling towards ‘South’.

Step 2: Calculate the distance
A change of 1° of latitude corresponds to a distance of 60 NM. Therefore,

• Distance (NM) = ch.lat (°) x 60 NM
• Distance = 3°16' x 60 NM
• Distance = 196 NM

2. LONGITUDE CALCULATION
Step 1: Calculate the change in longitude (ch.long)

• For same hemispheres, subtract the smaller longitude from the larger one.
• For different hemispheres, add the two longitudes

Since both positions lie in the Eastern Hemisphere, we will subtract the longitudes. Therefore,

• Change in longitude = E030°58' - E028°18'
• Change in longitude = 02°40'E*

* We are travelling towards ‘East’.

Step 2: Calculate the distance
The length of 1° of longitude varies with latitude. Therefore, the ‘departure’ formula is used to calculate the east–west distance.
Mean latitude: (Lat 1 + Lat 2) /2 = (S26°42' + S29°58') = S28°20'

• Departure (NM) = ch.long (°) x cos (mean lat) x 60
• Departure = 02°40' x cos (28°20') x 60
• Departure = 141 NM

3. MAGNETIC TRACK CALCULATION
From the figure, a right-angled triangle is formed. Therefore,

• tan (angle) = Perpendicular / Base
• tan (angle) = Distance of ch.long / Distance of ch.lat
• tan (angle) = 141 NM / 196 NM
• tan (angle) = 0.72
• angle = arctan (0.72)
• angle = 36°

Since the track is measured clockwise from True North. Therefore,

• True Track: 180° - 36° = 144°

180° is the angle from True North to the base, and the angle between the base and the hypotenuse is 36°.
Now, use the given variation to convert the true track to magnetic track.

• Using the mnemonic “VARIATION WEST → MAGNETIC BEST”
• Magnetic Track: 144°(T) + 25°W = 169°(M)

4. MAGNETIC HEADING CALCULATION
Since no wind information is provided for calculating the heading, we can assume there is no drift. Therefore,

• Magnetic Track = Magnetic Heading → 169°(M)

Therefore, the closest answer is: Magnetic Heading = 170°(M)